Question

@Uri @bibby

Can you answer this?

Choose the slope-intercept equation of the line that passes through the point (2, -3) and is perpendicular to y = two thirdsx + 3.
Choose one answer.
a. y = -three halvesx
b. y = three halvesx - 6
c. y = -two thirdsx - 5 thirds
d. y = two thirdsx - 13 thirds

Answer 1

what is the slope of a line perpendicular to \( y = \frac{2}{3}x + 3\)?

Answer 2

wat do u mean?

Answer 3

what is the slope of the line we want?

Answer 4

3 is slope.

Answer 5

lmao.

Answer 6

y=mx+b where m is the slope

Answer 7

ily uri

Answer 8

2/3

Answer 9

^

Answer 10

perpendicular lines have negative reciprocal slopes of the original lines

Answer 11

dat means?

Answer 12

reciprocals are "flipped". \(\large \frac{6}{5}\longrightarrow\frac{5}{6}\)

Answer 13

negative reciprocals are negated&& flipped 6/5->-5/6

Answer 14

i think its c.

Answer 15

nope

Answer 16

guess each letter until you exhaust all possibilities

Answer 17

no not fair to you or myself.

Answer 18

what is the negative reciprocal of \(\frac{2}{3}\)

Answer 19

3/2?

Answer 20

negative. negate it

Answer 21

-3/2

Answer 22

b?

Answer 23

why not a

Answer 24

to find a line that passes through (2, -3) with a slope of -3/2
\(y-y_1=\frac{-3}{2}(x-x_1)\)
\(y--3=\frac{-3}{2}(x-2)\)
\(y+3=\frac{-3}{2}(x-2)\)
\(\large y+3=\frac{-3}{2}x-\frac{-3}{\cancel{2}}*\cancel {2}\)
\(\large y+3=\frac{-3}{2}x+3\) subtract 3 from both sides
\(\large y=\frac{-3}{2}x\) subtract 3 from both sides