Question

tan(sin^-1 (5/6) - cos^-1(1/7))
help please.

Answer 1

hey I think I can help you :)

Answer 2

First step:
Let a=arcsin(5/6) and let b=arccos(1/7)
can you express tan(a-b) so that is in terms of tan(a) and tan(b)

Answer 3

The will be the second step in our process.

Answer 4

I know the formula is (tan a - tan b)/1- tan a(tan b)
and I get ((5/sqrt11) - (4 sqrt3))/1-(5 sqrt11)(4 sqrt3)
have no idea ow to simplify.

Answer 5

\[\tan(a-b)=\frac{\frac{\sin(a)}{\cos(a)}-\frac{\sin(b)}{\cos(b)}}{1+\frac{\sin(a)}{\cos(a)} \frac{\sin(b)}{\cos(b)}} \ \cdot \frac{\cos(a)\cos(b)}{\cos(a)\cos(b)} \\ =\frac{\sin(a) \cos(b)-\sin(b)\cos(a)}{\cos(a)\cos(b)+\sin(a)\sin(b)} \]

Answer 6

you are given sin(a)=5/6 and cos(b)=1/7