Question

help! medals rewarded
What are the amplitude, period, and phase shift of the given function?
f(t)=-1/2sin(4t-2pi)

Answer 1

the amplitude should be the easiest number to spot in these

Answer 2

f(x)=a*sin(bt+c)
The number a tells us the height the function will stretch from the graph's "middle axis" (this is the axis I like to call middle because it is in the center of the graph)
For f(x)=sin(x) the "middle axis" is y=0 and from it the graph stretches up 1 and stretches down 1
this is because the number in front of sin(x) is 1 (it would have the same amplitude if it was f(x)=-sin(x)
What I'm saying it the amplitude is simply |a|
Now the period? the period of y=sin(x) is 2pi
so the period of y=sin(bx) is 2pi/b
Phase shift is where the graph starts one of its first periods? This number can be found by solving the inside=0.
That is in your case 4t-2pi=0

Answer 3

Summary:
if y=asin(bt+c)
amp=|a|
period=2pi/b
phase shift comes from solve bt+c=0

Answer 4

what do you think the amp is?

Answer 5

1/2

Answer 6

ok cool
period?

Answer 7

is it 1/2pi

Answer 8

2pi/4=1pi/2=pi/2
yeah

Answer 9

phase shift?

Answer 10

the same

Answer 11

lol yeah
also the reason the phase shift can be found from setting the inside=0
is because y=sin(x) has phase shift at x=0
that is its inside=0

Answer 12

you can use the same information I gave you above for y=acos(bt+c)

Answer 13

thanks so much

Answer 14

np