An impure sample containing phosphoric acid was completely neutralized with strong base. The titration required 90.0M NaOH solution. calculate the equivanent weight of the acid how many moles of protons were titrated how many moles and grams of H3PO4 were titrated
I think we need more info, like V of NaOH
Sorry 90.0ml of 0.222 M NaOH
Have you solved the first problem?
no
Ok, first calculate the moles of NaOH. Then apply it into the equation \(3NaOH+H_3PO_4\rightarrow Na_3PO_4+3H_2O\) 3 moles 1 moles n moles ? moles \(n_{H_3PO_4}=n_{NaOH}\times 1 \div 3\)
how do we get the N values
0.222=x ----- .09L for moles
moles= 0.0198moles NaOh
could we use the molarity M= moles/L 0.22=moles/.09
Sorry, inappropriate formula
Yes. That one
And by the way, we are solving #3, sorry
ok
For the first one, \(\Large equivalent~weight =\frac{molar~mass}{numbers~of~H}\)
we are using the molar mass of H3PO4 for that one or NaOH
97.963g H3PO4 ------------- 3 for (h3)
\(H_3PO_4\). We can use that formula to any acids. For bases, we use \(\Large equivalent~ weight=\frac{molar ~mass}{numbers ~of ~OH}\)
=32.654
Correct
okay for the 3rd one we have 0.0198moles NaOh where do we go from that to get the moles or was that it
we have to relate that using the balanced equation
Yes. Based on the equation, 3 moles of NaOH will react with 1 moles of H3PO4. Then 0.0198 moles of NaOH will react with....
0.0198 moles NaOh 1 mole H3PO4 ------------------ X----------------= .0066 moles H3PO4 1 3 moles NaOH .0066 moles H3PO4 97.963g H3PO4 ------------------ x---------------- = .64656 g H3PO4 1 1 mole H3PO4
Exactly. Good job
how do we find the moles of protons
Actually, protons in this problem is \(H^+\). As you know, \(H\) has 1 p and 1 e. When it is \(H^+\), there is 1 p left
All you need to do is to find the moles of \(H^+\)
in NaOH or H3PO4
Only acids produce \(H^+\). Bases produce \(OH^-\)
so we will use the weak acid H3PO4 .0066 moles H3PO4 3 moles H ----------------- x -----------------=.0198 1 1 mole H3PO4
.0198 moles H
Right
Well done
and that equals the number of my protons
or should i take it to grams
The moles of your protons :) No, the problem asks for the moles of protons, not its mass
oh okay thank you very much for all of your help, its sometimes hard to relate all the knowledge into one problem
You are welcome. And yes, it is
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