Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

for what value of the numbers a and b does the function below have maximum value f(2)=4 f(x)=axe^(bx^2) also f'(x) and f(x) must equal for when the max occurrs at x=?x

OpenStudy (anonymous):

First find the derivative: \[f'(x)=ae^{bx^2}+2abx~e^{bx^2}\] Find the critical points: \[ae^{bx^2}+2abx~e^{bx^2}=0~~\iff~~1+2bx=0\] You can find (x\) in terms of \(b\). Knowing that a max is supposed to occur when \(x=2\), you will be able to find what value \(b\) would take on. To find \(a\), you would substitute your solution for \(b\) and the given value for \(f(2)\), then solve the resulting equation for \(a\). \[f(2)=4=2ae^{4b}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!