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for what value of the numbers a and b does the function below have maximum value f(2)=4 f(x)=axe^(bx^2) also f'(x) and f(x) must equal for when the max occurrs at x=?x
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First find the derivative: \[f'(x)=ae^{bx^2}+2abx~e^{bx^2}\] Find the critical points: \[ae^{bx^2}+2abx~e^{bx^2}=0~~\iff~~1+2bx=0\] You can find (x\) in terms of \(b\). Knowing that a max is supposed to occur when \(x=2\), you will be able to find what value \(b\) would take on. To find \(a\), you would substitute your solution for \(b\) and the given value for \(f(2)\), then solve the resulting equation for \(a\). \[f(2)=4=2ae^{4b}\]
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