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Physics 8 Online
OpenStudy (anonymous):

Two point charges, q1 and q2, are placed a distance r apart. The electric field is zero at a point P between the charges on the line segment connecting them. We conclude that: the answer is q1 and q2 have the same signs but different magnitudes. any idea as to why this is?

OpenStudy (ookawaiioo):

like charges repel

OpenStudy (anonymous):

For any point \(x\) away from charge \(q_1\) along the line connecting it to \(q_2\) we can determine the contributions of both electric fields \(E_1,E_2\) from \(q_1,q_2\) as follows: $$E_1\propto{q_1}/x^2\\E_2\propto q_2/(r-x)^2$$The point is that the electric field at some point in between is merely the sum of the contributions from the original electric fields (this is called superposition):$$E=E_1+E_2$$Now, for the electric field to be zero at some point, it follows that \(E=0\) so in other words \(E_1,E_2\) must cancel out. Since the denominators of both are guaranteed to be positive (\(x^2,(r-x)^2>0\)) it follows that the only way for them to cancel is for \(q_1,q_2\) to have opposite sign -- one must be positive and the other must be negative.

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