Two point charges, q1 and q2, are placed a distance r apart. The electric field is zero at a point P between the charges on the line segment connecting them. We conclude that: the answer is q1 and q2 have the same signs but different magnitudes. any idea as to why this is?
like charges repel
For any point \(x\) away from charge \(q_1\) along the line connecting it to \(q_2\) we can determine the contributions of both electric fields \(E_1,E_2\) from \(q_1,q_2\) as follows: $$E_1\propto{q_1}/x^2\\E_2\propto q_2/(r-x)^2$$The point is that the electric field at some point in between is merely the sum of the contributions from the original electric fields (this is called superposition):$$E=E_1+E_2$$Now, for the electric field to be zero at some point, it follows that \(E=0\) so in other words \(E_1,E_2\) must cancel out. Since the denominators of both are guaranteed to be positive (\(x^2,(r-x)^2>0\)) it follows that the only way for them to cancel is for \(q_1,q_2\) to have opposite sign -- one must be positive and the other must be negative.
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