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Mathematics 12 Online
OpenStudy (anonymous):

2 corrected exams are being returned to each of n students. How many ways can the teacher give those 2 exams back to each student such that everyone receives at least 1 exam that is not his.

OpenStudy (anonymous):

@satellite73 @jim_thompson5910 @dumbcow @dan815

OpenStudy (anonymous):

@Zarkon @wio @perl

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

lol @kropot72

OpenStudy (kropot72):

For each set of 2 corrected exams for a particular student there are 2 combinations where only one returned exam is his and the other returned exam is not his. Therefore there are 2^n ways of returning the exams where exactly one of each student's exams is not his. There are n! possible permutations of the n correctly returned exams for each of the 2^n ways of returning exactly one exam that is not his to each student. In many of these permutations students will receive 2 exams that are not theirs. Therefore the number of ways that the teacher can give those 2 exams back to each student such that everyone receives at least 1 exam that is not his is given by: \[\large 2^{n} \times n!\]

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