Question

Please help with these Algebra 2 questions. I'll give a medal.

1. What value completes the square for the expression? x^2+14x
2. Use the quadratic formula to solve the equation. x^2-7x-6=0
3. What are the solutions? 1/2x^2+2x+3=0

Answer 1

Completing the square
- This only applies if the coefficient of x^2 is 1. okay?
1. Identify the middle term-the term with x as the variable.
(In this case, it's 14)
2. Divide the numerical coefficient of the middle term by 2
(14/2 = 7)
3. To get the third term, square the quotient from step 2.
(7^2 = 49)
Then you'll have it as
\[x^2 + 14x +49\]

Answer 2

Standard equation:
\[ax^2 + bx + c = 0\]
Quadratic Formula:
\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 3

\[x^2-7x-6=0\]
\[a=1\]
\[b=-7\]
\[c=-6\]

Answer 4

Just plug in the values to the formula

Answer 5

is this\[\frac{1}{2}x^2+2x+3=0 \]

Answer 6

@KatieBear ?

Answer 7

yeah, it is. Sorry, I was eating breakfast. lol

Answer 8

\[\frac{ 1 }{ 2 }x^2 + 2x + 3 = 0\]
Multiply the whole equation by 2
\[x^2 + 4x + 6 = 0\]
Use quadratic equation
a = 1
b = 4
c = 6
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I'm pretty sure that the roots are imaginary xD

Answer 9

*quadratic formula

Answer 10

Thank you so much! I have a test today and now I understand the material so much better. :)

Answer 11

yw =)