Question

a line passes through the points (6, -2) and (5,-1) what is the x- intercept of the line ? who can show work for me please can you? i need help on this one @aum

Answer 1

First, you know that the line has an equation :
\[y=mx+b\]
So you have to find m and b.
for m we have :
\[m=\frac{y_2-y_1}{x_2-x_1}\] Where :
\[(x_1,y_1)\text{ and }(x_2,y_2)\]
are two points from the line.
Can you calculate m ?

Answer 2

thanks i get that part now (: whats next ? how can i calculate m ?

Answer 3

@Noura11

Answer 4

The exercise says : "a line passes through the points (6, -2) and (5,-1)"
So
\[(x_1,y_1)=(6,-2)\text{ and } (x_2,y_2)=(5,-1).\]
Did you get it ?
Please, try to calculate m :)

Answer 5

whats the answer then ?

Answer 6

@Noura11

Answer 7

First thing to consider is the slope of the line to get the equation
\[m = \frac{ y_2-y_1 }{ x_2-x_1 }\]
\[m = \frac{ -1-(-2) }{ 5-6 }\]
\[m = -1\]
------------------------
Plug in to point slope form using one point. Let's have (6,-2)
Point-slope form:
\[(y-y_1) = m(x-x_1)\]
\[y - (-2) = -1(x-6)\]
\[y+2 = -x +6\]
\[y = -x + 6 - 2\]
\[y = -x +4\]
-----------------------
Since you are looking for the x-intercept, note that y=0
y = -x + 4
0 = -x + 4
x = 4

Answer 8

thankyouuuuuu guys for helping !!

Answer 9

@shinalcantara @Noura11