What quadrant is 11pi/3 in? Find sin, cos, and tan theta.
is there a way to do this besides looking at the unit circle because I am confused on where to find 11pi/3
@Jaynator495 @taylor12344 @ParthKohli
im sorry i dont know how to explain it without giving the answer away, and as thats not allowed ill try and call someone who can help more with this :)
@just_one_last_goodbye @TheSmartOne
\[ \frac{11\pi}{3} = \frac{9\pi+2\pi}{3} = 3\pi + \frac 23\pi = 2\pi + \pi + \frac 23 \pi \]
figures, the one i didnt call but htought of came and helped lol
\[2\pi + \pi + \frac 23\pi\]\(2\pi\) is one full circle and can be ignored. \[\pi + \frac 23 \pi = \pi + \frac 12 \pi + \frac 16\pi\] In which quadrant does that lie?
@aum do u know
dont struggle with it, its fine guys, i gtg anyway. aum u can always comment here or message me if u wanna help me out, i appreciate it
\[ \pi + \frac 12 \pi + \frac 16\pi \\ \pi = 180 \text{ degrees} \\ 180 + 90 + 30 = 300 \text{ degrees}. \]
Which quadrant is 300 degrees?
1?
i mean 4 srry
Yes.
Do i find sin cos and tan theta by looking at the parenthesis on the unit circle
If radians is confusing, convert it to degrees and it will be easier to figure out the quadrant.
i need to figure out the next part now ^^
The first value within the parenthesis, that is the x-coordinate is the cosine value and the y-coordinate is the sine value.
can u check my answers for that
cos= -1/2 sin= (-sqrt 3)/2 tan= sqrt 3 pretty sure the last one is right, and maybe the sin
cosine is positive in the fourth quadrant and so it should be 1/2 (not -1/2). tangent is negative in the fourth quadrant.
\[ \cos\left( \frac{11\pi}{3} \right) = \frac 12 \\ \sin\left( \frac{11\pi}{3} \right) = -\frac {\sqrt{3}}{2} \\ \tan\left( \frac{11\pi}{3} \right) = -\sqrt{3} \\ \]
thanks!!! @aum
yw.
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