Question

4.6g C-H-O compound contains 0.2 mol C and 1.6g O. Find the empirical formula of this compound?
C:12g/mol; O:16g/mol; H:1g/mol

Answer 1

C=2.4 g and O = 1.6 g => 2.4+1.6 =4.0 g
4.6 g - 4.0 g = 0.6 g H
then I find moles with using all g so ;
0.1 mol O , 0.2 mol C and 0.6 mol H and finally x10 ;
C2H6O ,,,,,,,, Is it true ?

Answer 2

Yes that is true

Answer 3

thanks

Answer 4

Yep no problom

Answer 5

How old are you