Question

Year 3, F(3) = 150(1.02)^3 = 159.

Year 5, F(5) = 150(1.02)^5 =166

Year 7, F(7) = 150(1.02)^7 = 172

What would be the average rate of change between year 3 and 5 and the rate of change between 5 and 7.

Answer 1

So for years 3 and 5 this is what i have so far.\[\frac{ f(5) - f(3) }{b - a }\]

Answer 2

is this correct or not?

Answer 3

@cwrw238

Answer 4

Thats not correct but could someone please help meee

Answer 5

@ganeshie8

Answer 6

@jim_thompson5910

Answer 7

from 3 to 5, you replace b with 5 and a with 3

\[\Large \frac{ f(5) - f(3) }{b - a } = \frac{ f(5) - f(3) }{5-3 } = ??\]

Answer 8

So thats what you would do for the top half of the formula what would you do for the bottom half?

Answer 9

5-3 is 2 so if both of them were 5-3 it would end up being 2/2 which would be 1

Answer 10

just do 5-3 = 2 for the bottom half

Answer 11

f(5)-f(3) is not equal to 2 though

Answer 12

it's equal to the difference in the outputs you got at the top

Answer 13

What is it equal to?

Answer 14

Year 3, F(3) = 150(1.02)^3 = 159.

Year 5, F(5) = 150(1.02)^5 =166

Answer 15

assuming you did that correctly

Answer 16

Ohhh i see

Answer 17

7/2

Answer 18

So now that i have 7/2 what would i do next

Answer 19

Or would that be it? is the question complete?

Answer 20

yeah that is the approximate avg rate of change

Answer 21

Okay so would i just do the same for year 5 through 7?

Answer 22

correct

Answer 23

Okay if i have any other questions ill ask you!!