Need Help Please! Not just the answer! Find the quadratic equation with roots -1+4i and -1-4i
If the roots are -1+4i or -1-4i then x = -1+4i or x = -1-4i
the goal is to get everything in each equation to the left side. This is so you are left with 0 on the right side
so 0=-x-1-4i?
x = -1 + 4i x+1 = -1 + 4i + 1 ... Add x to both sides. x+1 = 4i
recall that i = sqrt(-1) to get rid of that 'i', you square both sides (to undo the square root)
how do you sqrt x+1?
so let's do so... x+1 = 4i (x+1)^2 = (4i)^2 (x+1)^2 = 4^2*i^2 (x+1)^2 = 16i^2 (x+1)^2 = 16(-1) (x+1)^2 = -16 now we can move the last bit to the other side (x+1)^2+16 = -16+16 ... Add 16 to both sides. (x+1)^2 + 16 = 0
you square (x+1) NOT square root (x+1)
Oh! Okay I got you.
so you see how I got (x+1)^2 + 16 = 0 ?
Yes.
ok let's do the same for x = -1 - 4i
you'll see that the steps are nearly identical
Okay, and then do you do the quadratic formula ?
x = -1-4i x+1 = -4i (x+1)^2 = (-4i)^2 (x+1)^2 = 16i^2 (x+1)^2 = 16(-1) (x+1)^2 = -16 (x+1)^2 + 16 = 0
so as you can see, the two roots lead to (x+1)^2 + 16 = 0
you use the quadratic formula to find the roots if you know the quadratic
In this case, we don't know the quadratic but we know the roots
anyways, the last step is to expand and simplify (x+1)^2 + 16
So x^2 + 2x +17?
you nailed it
now if you used the quadratic formula for x^2 + 2x +17, you'll find that the roots are -1+4i and -1-4i
so this is like thinking backwards
Okay I get it now . Thank you so much for your help
you're welcome
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