Question

help!

Answer 1

@sourwing

Answer 2

@myininaya its still disconnecting

Answer 3

What do you mean?

Answer 4

i put up this question a second ago, and it showed that you were responding but i couldnt see anything... i dont know whats going on with openstudy lately

Answer 5

could you explain this question please? (:

Answer 6

\[V = x^2h \]
V,x, and h are all functions of time
Can you differentiate V=x^2h w.r.t t?

Answer 7

2hx

Answer 8

@myininaya

Answer 9

\[\frac{d x^2}{dt}=2xx'\]
You are going to have to use product rule to find the derivatie of (x^2h) w.r.t t.

Answer 10

\[\frac{dV}{dt}=\frac{d(x^2h)}{dt} \\ \frac{dV}{dt}=x^2 \frac{d h}{dt}+h \frac{d x^2}{dt}\]

Answer 11

by product rule

Answer 12

now you already know the derivative of x^2 w.r.t t

Answer 13

now just plug in your values

Answer 14

okk

Answer 15

i was right about 192 right?

Answer 16

yes but not sure how you got it with 2xh

Answer 17

i got increasing at 192 but i thought i was wrong haha thats why i tried a different approach

Answer 18

lol well it looks like the different approach worked