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Mathematics 12 Online
OpenStudy (anonymous):

complex numbers homework, will fan and medal

OpenStudy (anonymous):

Square root of negative 75?

OpenStudy (anonymous):

If you factor 75, you get 3*5*5 so pull the 5*5 out of the square root and make it 5. Then the i(the negative part) falls in love with the 5's and tags along for the ride and thus only the 3 is left under the square root. \[5i \sqrt{3}\]

OpenStudy (anonymous):

thank you very much, would you mind helping with a few more? so i can really get the grasp of it

OpenStudy (anonymous):

i can make new questions if you want more medals

OpenStudy (anonymous):

No, just ask them here <3. I would be glad to help.

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

Have you heard the song It's Not Unusual by Tom Jones

OpenStudy (anonymous):

\[\sqrt{98}\]

OpenStudy (anonymous):

and no, why do you ask?

OpenStudy (anonymous):

I heard it recently and I think its good

OpenStudy (anonymous):

ill give it a listen soon :)

OpenStudy (anonymous):

Okay great. Now hit me with those questions.

OpenStudy (anonymous):

\[\sqrt{98}\]

OpenStudy (anonymous):

i could just solve that in a calculator but my teacher wouldn't accept it lol

OpenStudy (anonymous):

Okay for square root problems, always think about ways to break down the number under the square root into smaller numbers. So for 98 it would be 2*7*7

OpenStudy (anonymous):

Then you pull out the perfect square and it becomes 7sqrt(2)

OpenStudy (anonymous):

i get that, but the way my teacher taught me looks different than yours so i'm trying to get used to it @ArkGoLucky

OpenStudy (anonymous):

Oh. What way did your teacher teach you.

OpenStudy (anonymous):

ill post a picture, one minute

OpenStudy (anonymous):

well, idk, he talked about imaginary numbers and perfect squares

OpenStudy (anonymous):

Well it seems to be that is the same method as the one I am using

OpenStudy (anonymous):

like, \[\sqrt{-50}\] = 5i(sqrt)2

OpenStudy (anonymous):

So what way would you solve this if not the one I used?

OpenStudy (anonymous):

he puts the answer inside of a sqrt sign so it just looks different.

OpenStudy (anonymous):

its okay though, whatever works

OpenStudy (anonymous):

Oh. Well you can tell your teacher that this random person on the Internet thinks his method is pretty useless.

OpenStudy (anonymous):

lolololol okay

OpenStudy (anonymous):

Yeah sorry. I'm just a little confused as what is the difference between our methods. Do you have any other questions?

OpenStudy (anonymous):

i actually like this way better

OpenStudy (anonymous):

yeah i have like 7 more problems lol

OpenStudy (anonymous):

Keep'em coming. By the way, is your profile picture a picture of you. Those are some awesome tattoos.

OpenStudy (anonymous):

yeah thats me, and thank you, i love them :)

OpenStudy (anonymous):

they were costy though

OpenStudy (anonymous):

but the next one is \[\sqrt{-500}\]

OpenStudy (anonymous):

Okay same process. First take out the negative so that it becomes -1*500. Then split 500 into factors. 500-> 5*10*10. Pull out the The result is really \[\sqrt{-1}*\sqrt{100}*\sqrt{5}\]

OpenStudy (anonymous):

That becomes i*10*sqrt(5)

OpenStudy (anonymous):

hm..that makes sense

OpenStudy (anonymous):

\[\sqrt{64}\] this should be easy i bet lol

OpenStudy (anonymous):

8

OpenStudy (anonymous):

no solving requires since its a perfect square im assuming?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

easy enough =)

OpenStudy (anonymous):

\[\sqrt{-45}\]

OpenStudy (anonymous):

i3sqrt(5)

OpenStudy (anonymous):

is that all? no numbers to break it down?

OpenStudy (anonymous):

3*3*5*i so you can pull out the 3

OpenStudy (anonymous):

so the answer looks like i3\[\sqrt{5}\]?

OpenStudy (anonymous):

or would it be 3i

OpenStudy (anonymous):

3i is the same as i3. Whatever you are more comfortable with

OpenStudy (anonymous):

ah okay :D

OpenStudy (anonymous):

sqrt 162

OpenStudy (anonymous):

2*9*9 so 9sqrt(2)

OpenStudy (anonymous):

only a couple more now

OpenStudy (anonymous):

\[\sqrt{-72}\]

OpenStudy (anonymous):

-1*6*6*2= 6isqrt(2)

OpenStudy (anonymous):

sqrt 20

OpenStudy (anonymous):

2*2*5 =2sqrt(5)

OpenStudy (anonymous):

-32

OpenStudy (anonymous):

-1*4*4*2=4isqrt(2)

OpenStudy (anonymous):

last one is sqrt 125

OpenStudy (anonymous):

5*5*5=5sqrt(5)

OpenStudy (anonymous):

i actually understand it now, this was better than the actual class lol. thank you so much for everything, i'm gonna go listen to that song. have a nice night :)

OpenStudy (anonymous):

You're welcome. Good night to you too.

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