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OpenStudy (anonymous):
Square root of negative 75?
OpenStudy (anonymous):
If you factor 75, you get 3*5*5 so pull the 5*5 out of the square root and make it 5. Then the i(the negative part) falls in love with the 5's and tags along for the ride and thus only the 3 is left under the square root. \[5i \sqrt{3}\]
OpenStudy (anonymous):
thank you very much, would you mind helping with a few more? so i can really get the grasp of it
OpenStudy (anonymous):
i can make new questions if you want more medals
OpenStudy (anonymous):
No, just ask them here <3. I would be glad to help.
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OpenStudy (anonymous):
thanks :)
OpenStudy (anonymous):
Have you heard the song It's Not Unusual by Tom Jones
OpenStudy (anonymous):
\[\sqrt{98}\]
OpenStudy (anonymous):
and no, why do you ask?
OpenStudy (anonymous):
I heard it recently and I think its good
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OpenStudy (anonymous):
ill give it a listen soon :)
OpenStudy (anonymous):
Okay great. Now hit me with those questions.
OpenStudy (anonymous):
\[\sqrt{98}\]
OpenStudy (anonymous):
i could just solve that in a calculator but my teacher wouldn't accept it lol
OpenStudy (anonymous):
Okay for square root problems, always think about ways to break down the number under the square root into smaller numbers. So for 98 it would be 2*7*7
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OpenStudy (anonymous):
Then you pull out the perfect square and it becomes 7sqrt(2)
OpenStudy (anonymous):
i get that, but the way my teacher taught me looks different than yours so i'm trying to get used to it @ArkGoLucky
OpenStudy (anonymous):
Oh. What way did your teacher teach you.
OpenStudy (anonymous):
ill post a picture, one minute
OpenStudy (anonymous):
well, idk, he talked about imaginary numbers and perfect squares
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OpenStudy (anonymous):
Well it seems to be that is the same method as the one I am using
OpenStudy (anonymous):
like, \[\sqrt{-50}\] = 5i(sqrt)2
OpenStudy (anonymous):
So what way would you solve this if not the one I used?
OpenStudy (anonymous):
he puts the answer inside of a sqrt sign so it just looks different.
OpenStudy (anonymous):
its okay though, whatever works
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OpenStudy (anonymous):
Oh. Well you can tell your teacher that this random person on the Internet thinks his method is pretty useless.
OpenStudy (anonymous):
lolololol okay
OpenStudy (anonymous):
Yeah sorry. I'm just a little confused as what is the difference between our methods. Do you have any other questions?
OpenStudy (anonymous):
i actually like this way better
OpenStudy (anonymous):
yeah i have like 7 more problems lol
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OpenStudy (anonymous):
Keep'em coming. By the way, is your profile picture a picture of you. Those are some awesome tattoos.
OpenStudy (anonymous):
yeah thats me, and thank you, i love them :)
OpenStudy (anonymous):
they were costy though
OpenStudy (anonymous):
but the next one is \[\sqrt{-500}\]
OpenStudy (anonymous):
Okay same process. First take out the negative so that it becomes -1*500. Then split 500 into factors. 500-> 5*10*10. Pull out the The result is really \[\sqrt{-1}*\sqrt{100}*\sqrt{5}\]
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OpenStudy (anonymous):
That becomes i*10*sqrt(5)
OpenStudy (anonymous):
hm..that makes sense
OpenStudy (anonymous):
\[\sqrt{64}\] this should be easy i bet lol
OpenStudy (anonymous):
8
OpenStudy (anonymous):
no solving requires since its a perfect square im assuming?
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
easy enough =)
OpenStudy (anonymous):
\[\sqrt{-45}\]
OpenStudy (anonymous):
i3sqrt(5)
OpenStudy (anonymous):
is that all? no numbers to break it down?
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OpenStudy (anonymous):
3*3*5*i so you can pull out the 3
OpenStudy (anonymous):
so the answer looks like i3\[\sqrt{5}\]?
OpenStudy (anonymous):
or would it be 3i
OpenStudy (anonymous):
3i is the same as i3. Whatever you are more comfortable with
OpenStudy (anonymous):
ah okay :D
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OpenStudy (anonymous):
sqrt 162
OpenStudy (anonymous):
2*9*9 so 9sqrt(2)
OpenStudy (anonymous):
only a couple more now
OpenStudy (anonymous):
\[\sqrt{-72}\]
OpenStudy (anonymous):
-1*6*6*2= 6isqrt(2)
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OpenStudy (anonymous):
sqrt 20
OpenStudy (anonymous):
2*2*5 =2sqrt(5)
OpenStudy (anonymous):
-32
OpenStudy (anonymous):
-1*4*4*2=4isqrt(2)
OpenStudy (anonymous):
last one is sqrt 125
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OpenStudy (anonymous):
5*5*5=5sqrt(5)
OpenStudy (anonymous):
i actually understand it now, this was better than the actual class lol. thank you so much for everything, i'm gonna go listen to that song. have a nice night :)