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Differentiate the function. F(x)=ln rad x. I switched it to ln x^(1/2) since I'm not good with radicals
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thats a good start, heard of chain rule before ?
yup is that what needs to be done for x^(1/2)? In my book it says the answer is F'(x)=1/(2x) but I have no idea how they got that
Yeah you can avoid chain rule for now by using log properties
\[\large \rm F(x) = \ln \sqrt{x} = \ln x^{1/2} = \dfrac{1}{2} \ln x\]
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Now differentiate
ok I got it thank you :)
yw:)
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