-3x+2y>5y+9
So whats the question regarding this inequality?
I am lost when it comes to this and have been trying to figure out how to solve this
This inequality has two variables and so, it is unsolvable if the two variables are unknown? Do you need to find x or y?
it wanted to know which is equivalent and they gave me 4 answers but i dont know how to solve it to get the answer
-3x +2y > 5y + 9 -3x > 5y (-2y) + 9 -3x > 3y + 9 multiply across by -1 change sign 3x < -3y + 9 divide by 3 x < -y + 3
Does that answer fit any of the four answers they gave you?
no but let me see what you did so i can try and figure it out
so do i divide by 3 for all?
answer is actually x > -y-3 sorry
see i got y>x+3
none of the answers but mine were one of the options
it cant be thats not one of my options
well maybe if i solved for y then it would be -x-3>y
Okay, step by step, here we go: step 1: subtract 2y from both sides -3x +2y (-2y) > 5y (-2y) + 9
did that
gives: -3x > 3y + 9
ok
step 2: multiply across by -1 to get rid of minus sign -1 (-3x ) > -1(3y + 9) => 3x > -3y -9
but why multiply by -1 thats where you lost me
now need to reverse sign when you multiply by a negative number so it becomes: 3x < -3y -9
I multiplied by -1 becuase I have -3x but I want x to be positive
ok that makes sense
ok
so final step is divide both sides of 3x < -3y -9 by 3 to get x < -y -3
Then take a bow!LOL
i did that but here are my answers: A: y>x+3 B;Y>-x-3 C. y<x-3 D. y<-x-3
so B?
okay we will get there
i hope so i have been at this for 4 hours!
LOL
i do nt see a -y anywhere?
so all answers are in terms of y, so we need to find answer in terms of y
ok
so lets add 3 to both sides of our answer to cancel -3 as follows: x (+ 3) < -y -3 (+3)
ok give me one sec im doing it
now we have x+3 < -y so to get ri of y we multiply across by -1: -1(x + 3) < -1(- y) -x -3 > y dont forget sign changes if you multiply by negative number
is this it 2y>5y+9+3x
now we can rewrite this with y on left hand sign but we also need to change sign y < -x -3
thank you so much for your help
youre welcome!
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