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How do you add radicals? Medals
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lmfao just did that stuff
\[\sqrt{10}+\sqrt{8}\]
I think it's \[\sqrt{18}\] am I right?
no you cannot add them
you can write \(\sqrt8=2\sqrt2\) if you like, but you cannot add them like that
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just like \(\sqrt{50}+\sqrt{50}\neq \sqrt{100}=10\)
umm so I can't add them? why not
Can I simplify it?
There's no way to simplify this down nicely, this is the best I can get: \[\sqrt{10}+\sqrt{8}=\sqrt{5*2}+\sqrt{4*2}=\sqrt{5}\sqrt{2}+\sqrt{4}\sqrt{2}=(\sqrt{5}+\sqrt{4})\sqrt{2}=(2+\sqrt{5})\sqrt{2}\]
@TaylorS11 because Maths doesn't work like that. \[\sqrt{9}+\sqrt{16} = 3 +4 = 7, \sqrt{9+16}=\sqrt{25}=5\] They aren't equal.
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Ugh math -_- whyy okay thanks
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