Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geometric sequence: -8, -16, -32, -64, -128, . . . . A. -2003 B. -2040 C. -2060 D. -2038
Alright, so all the terms in your sequence have the same sign; you know that they don't alternate. So there's nothing like \[(-1)^n\]involved. You can also see that the terms are doubling with every increase of n, for instance,\[a_{1}=-8,\]\[a_{2}=(2)(-8)=-16,\]\[a_{3}=(2)(-16)=-32,\]\[. \ .\ .\ \]
First, a_n should be found based on the information you can figure out from these terms. Can you find a general formula for a_n?\[a_n=\ ?\]
Since each term increases by two, is there anything you can do with putting two to some power, to get your general formula for a?
|dw:1416540044921:dw| Plug in the values and find the sum
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