HELP!! 7x^2+5=530 solve by taking square roots
I'll get you started \[\Large 7x^2+5=530\] \[\Large 7x^2+5-5=530-5\] \[\Large 7x^2=525\] \[\Large \frac{7x^2}{7}=\frac{525}{7}\] \[\Large x^2=75\] and I'll let you finish
the choices are:: a) {i square root 3, -i square root 3} b) {i square root 5} c) {5 square root 3, -5 square root 3} d) {5 square root 3}
@jim_thompson5910
do you see how I got to x^2 = 75
yea,, you divide 525 and 7
so we have x^2 = 75, what is x equal to? how do we find x?
by the 7x^2 divide by 7
\[\Large x^2 = 75\]
what undoes squaring?
i dont know
@jim_thompson5910
example take the number 5 and square it to get 25 to undo that, you square root 25 to get 5 back
so if we square x, we do what to undo that operation?
im just confuse cuz i got 75 but its not on the choices
you take the square root of that to isolate x \[\Large x = \pm\sqrt{75}\]
you simplify from there
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