Which of the following is a polynomial function in standard form with zeros at -8, -1, and 3?

f(x) = x^3 + 6x^2 - 19x - 24
f(x) = (x - 8)*(x - 1)*(x + 3)
f(x) = (x + 8)*(x + 1)*(x - 3)
f(x) = x^3 - 6x^2 - 19x + 24

I *think* it's C because that's adding the numbers there listed to the ones above would equal zero but I'm not sure

Question

Which of the following is a polynomial function in standard form with zeros at -8, -1, and 3?

f(x) = x^3 + 6x^2 - 19x - 24
f(x) = (x - 8)*(x - 1)*(x + 3)
f(x) = (x + 8)*(x + 1)*(x - 3)
f(x) = x^3 - 6x^2 - 19x + 24

I *think* it's C because that's adding the numbers there listed to the ones above would equal zero but I'm not sure

anonymous · Answer

yes you are correct factoring is sometimes called finding the zeros so when you completly factor a polynomial is is also called finding the zeros

anonymous · Answer

however c is in factored form not standard form

anonymous · Answer

i would factor a and d and see which one factors to the desired zeros

anonymous · Answer

How do I factor the polynomials?

paxpolaris · Answer

expand C instead ... and see if you get A or D

paxpolaris · Answer

$$f(x)\=(x+8)\left[ (x+1)(x-3) \right]\=\left( x+8 \right)\left[ x^2-2x-3 \right]\=?$$

anonymous · Answer

i was just about to tell him to multiply all the factors together

anonymous · Answer

I got -24...?

anonymous · Answer

multiply (x+8)(x+1)(x-3) you should not get -24

anonymous · Answer

pax polaris got it started

anonymous · Answer

(x+1)(x-3)= x^2-2x-3

anonymous · Answer

so multiply (x^2-2x-3)(x+8)

anonymous · Answer

-36....not quite sure if I'm doing this right

anonymous · Answer

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