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Integration question
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\[\int\limits_{0}^{\ln3}\int\limits_{0}^{\ln2} e^{x+y} dy dx\]
please you have to separate the variable, so you will calculate two integrals in one variable, namely: \[\int\limits_{0}^{\ln3}e ^{x}dx \int\limits_{0}^{\ln2}e ^{y}dy\]
...
if \[x \in (0,\ln3), y \in(0,\ln2)\]
he means\[\int\limits_{0}^{\ln3}[\int\limits_{0}^{\ln2}e^{x+y}dy]dx\]
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yes
now u can take out that e^{y} part when you are integrating with respect to x
so u'll get\[\int\limits_{0}^{\ln 3}e^x.dx[\int\limits_{0}^{\ln 2}e^y.dy]\]
that how its separated now u have a two parts one for x and one for y so first integrate e^{y}.dy part
So when i integrate it with respect to y will it be 2 e^x?
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