Question

The quadratic equation px^2+qx-36=0 has roots -2 and 6.Find
a)the values of p and q.

Answer 1

@ikram002p

Answer 2

so
since -2, 6 are roots then
(x+2)(x-6)=px^2+qx-36=0

Answer 3

expand (x+2)(x-6) can u do that ?

Answer 4

oh wait sorry

Answer 5

okay

Answer 6

the question has a mistake , it should be -12 not -36
but its ok
it can be solved in anotherway

Answer 7

k

Answer 8

so , -2 , and 6 are roots means
f(-2)=f(-6)=0

Answer 9

yes

Answer 10

f(x)=px^2+qx-36=0
f(-2)=4p-2q-36=0 .................... equation 1
f(6)=36 p +6q-36=0...................equation 2

Answer 11

could u solve the two linear equations now ?

Answer 12

i will try :)

Answer 13

good , try and tell me what u got
these are the equations
4p-2q=36
36p+6q=36