Question

Help with mixture problems?
Amy mixes 12 liters of 16% acid solution with a 40% acid solution which results in 32% acid solution.

Let x represent the number of liters of 40% solution used. Which equation can be used to find the number of liters of 40% acid solution in the mixture?

A. 1.92 + 0.32x = 0.4(x + 12)
B. 3.84 + 0.4x = 0.16(x + 12)
C. 4.8 + 0.32x = 0.4(x + 12)
D. 1.92 + 0.4x = 0.32(x + 12)

Please also show me HOW you got your answer. Thanks so much!

Answer 1

@Directrix @SolomonZelman

Answer 2

@ganeshie8 @cwrw238

Answer 3

the volume of pure acid in 12 liters of 16% strength = 12*0.16 = 1.92 liters
and for the 40% solution its 0.40 x where x is the volume required
the resulting mixture contains 32% of pure acid and its volume is x + 12 liters
so volume of pure acis is 0.32(x + 12)
so we have
1.92 + 0.40x = 0.32(x + 12)

Answer 4

option D

Answer 5

Ok, thank you so much!

Answer 6

yw