The distance from the top of the archery is 1.5 m if you release at a height of 1.39m and the arrow hits 18m away what is the quadratic equation?

Question

The distance from the top of the archery is 1.5 m if you release at a height of 1.39m and the arrow hits 18m away  what is the quadratic equation?

anonymous · Answer

ax^2+bx+c=0

anonymous · Answer

$$-b \pm \sqrt{b ^{2}-4ac}/2a$$

anonymous · Answer

got it? @hayhay5270

anonymous · Answer

No not really lol I tried but I cannot figure out the a b or c to solve the equation

anonymous · Answer

@Brostep0s

anonymous · Answer

are these your points?  (0, 1.39) (18,40) and (45,0).

anonymous · Answer

I just have the facts and my measurement that's it I have no clue

anonymous · Answer

well, those should be your points, if my calculations are correct.

anonymous · Answer

Okay  yeah so I'm just stuck on that part of finding the maximum height and the parabolic path

anonymous · Answer

use this for your equation: 0 = a(45)^2 +b(45) +1.39

anonymous · Answer

should come out to 1.41 if you do everything correctly.

anonymous · Answer

How would I solve that? I'm not to good at algebra

anonymous · Answer

a=45 b=45 c=1.39 $$-b \pm \sqrt{b ^{2}-4ac}/2a$$

anonymous · Answer

Okay that's whatis got so 1.41 is my max height ?

anonymous · Answer

yeppers

anonymous · Answer

Okay thanks!

anonymous · Answer

cx

anonymous · Answer

;)