In a relay race, the probability that team Sapphire wins is 22%. In another unrelated relay race, the probability that team Emerald wins is 47%. What are the chances that both teams lose their races?

Question

perl · Answer

P(A & B ) = P(A) * P(B) , as long as A,B are independent

perl · Answer

here it says the races are 'unrelated' thats a clue we can assume independence

anonymous · Answer

i am horrible at all math could u guide me through it

perl · Answer

ok

perl · Answer

In a relay race, the probability that team Sapphire wins is 22%. In another unrelated relay race, the probability that team Emerald wins is 47%. What are the chances that both teams lose their races?

P(sapphire wins) = .22
P(sapphire loses) = 1-.22 = .78 

P( emerald wins) = .47
P( emerald loses) = 1- .47 = .53

P ( sapphire loses & emerald loses ) = P( sapphire loses) * P(emerald loses)

perl · Answer

now you can solve it by plugging in

perl · Answer

P stands for probability

anonymous · Answer

26.71?

perl · Answer

thats too big

perl · Answer

probability is between 0 and 1 :)

perl · Answer

P ( sapphire loses & emerald loses )
 = P( sapphire loses) * P(emerald loses) 
= .78 * .53

anonymous · Answer

Okay is the answer then .4134 which when multiplied by 100 turns to 41.34%