A bowling ball of mass 9 kg hits a wall going 11 m/s and rebounds at a speed of 8 m/s. What was the impulse applied to the bowling ball?

Question

noelgreco · Answer

Impulse is equal to change in momentum$$F \Delta t = m \Delta v$$

Calculate the change in momentum.

anonymous · Answer

Change in momentum is the same as impulse. The general formula for change in momentum is Mass*velocity(before collision)  - Mass*velocity(after collision).
You can simplify to m(u-v).
Another thing : your final velocity is in the opposite direction in realtion to the previous on, so your v-value is negative. Rearranging the formula you get m(u-[-v])=m(u+v). Replace the values and get your answer. Hope it did help.