Question

Solve the equation :)

Answer 1

\(x^3+1=x^2+x\)

I know I need to move the terms on the right to the left to get:
\(x^3-x^2-x+1=0\)

Answer 2

x= 1,-1

Answer 3

I have to show work, sadly :( I know I need to factor it and I can factor \(x^2\) out of the first two terms but that's pretty much it.... :(
\(x^2(x-1)-x+1=0\)

Answer 4

idk how to show the work sorry, i input it into an online calculator

Answer 5

:) it's okay :D

Answer 6

\(\large\color{black}{ x^3+1=x^2+x }\)
\(\large\color{black}{ x^3+1^3=x^2+x }\)
\(\large\color{black}{ (x+1)(x^2+2x+1)=x(x+1) }\)
\(\large\color{black}{ x^2+2x+1=x }\)
\(\large\color{black}{ x^2+x+1=0 }\)

Answer 7

how did you get \(1^3\)?

Answer 8

sorry it is -2x. and then it would be
\(\large\color{black}{ x^2-3x+1=0 }\)

Answer 9

and \(\large\color{blue}{ 1^3 }\) is just that I re-wrote \(\large\color{blue}{ 1 }\) this way.
I didn't change the value, did I :) ?

Answer 10

oh! true lol :)

Answer 11

SO yeah.. then you have left with \(\large\color{blue}{ x^2-3x+1=0 }\)

Answer 12

okay...then I just factor that and set both of the factors to equal 0, then bam! there's the answer :P lol

Answer 13

I don't think you can factor this equation, or can't factor into integers at least...

Answer 14

wouldn't it be +2? because there are no negatives at all on the left to begin with so I think you were right at first.....

Answer 15

and how would you get a 3x?

Answer 16

and how do you get 1?

Answer 17

eh? no! I meant +2x to begin with lol

Answer 18

I'm really confuzzled..... :/

Answer 19

use the quadratic formula, or complete the square... factoring is not the only method to solve quadratic equations .

Answer 20

true! :D uno momento por favor lol

Answer 21

I don't speak Spanish...

Answer 22

I know what this phrase means though.

Answer 23

one moment please is the translation

Answer 24

lol I don't really either but I know some haha (that meant one second please)

Answer 25

Si.

Answer 26

moment I mean lol

Answer 27

I do know Russian, Hebrew, and by far better than English. (Plus, "Yiddish" and "Arameic" the language of the "Talmud")

Answer 28

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] right? I only know some spanish and I mostly speak english :) except when I am in a spanish mood or say that phrase haha that's cool!

Answer 29

Yes you got the quadratic formula right... although I hate using it...
hate it so far so that I would complete the square in even the most ridiculous cases (if I can't factor).

Answer 30

well, you can go by it though...

Answer 31

lol I agree.....I think I will do complete the square method....one second