Find the quadratic equation with roots -1+ 4i and -1 - 4i
just write it in the form (x-a)(x-b)=0 and expand the brackets, where a and b are the given roots
so (4-1) (-4-1) ?
not sure what u mean - the roots are complex numbers
do you know the answer? maybe ill kind of get it more idk
have you met complex numbers before ?
No
you really need to know some complex algebra to tackle this question the i that appears in your question is the imaginary unit, defined so that i squared = -1 that's about all you need to know get the answer here
4i = -1 ?
im very bad at this erh
you need to read up on quadratic equations a bit
i really should
but could you show me how to do this step by step or nah...
do you understand what the root of a quadratic equation is ?
I believe so
ok, and any quadratic has 2 roots
if you call the roots a and b, then you can reconstruct the original equation by writing it as (x-a)(x-b)=0 and expanding the brackets
now in your particular example, a = -1+4i and b = -1-4i
so you have to expand (x+1-4i)(x+1+4i) = 0
just multiply out the brackets and remember that wherever you get i^2, you can replace it with -1
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