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Find the Derivative of 7e^(x+3)+e^-1
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\[7e ^{x+3}+e ^{-1}\]
what is the x
7(2.718281828459045x+3)+2.718281828459045−1
what do you mean? I need to find the derivative.
if you are Evaluate i need to find the x
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No, we do not need to find x just f'(x)
sorry i don't know
e^-1 is constant, then derivative =0
\(7e^{x+3}= 7(e^x.e^3)\)
ok
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so that it is 7e^3 e^x, the first 2 term are constant , so let them as they are., just the last one need to take derivative
(e^x)' = e^x
so that the whole thing is \(7e^{x+3}\)
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