Question

How do I solve these problems

Answer 1

use the product rule to find (fg)' what do you get ?

Answer 2

I do not understand how to use the product rule without the functions

Answer 3

can you write down the product rule ?

Answer 4

\[f'(x) = f(x)*g'(x) + g(x) * f'(x)\]

Answer 5

ok, except the left-hand side is (f(x) * g(x) )'

Answer 6

now replace x with -2 in your "rule"

Answer 7

and then look up the values in your table.

Answer 8

and
(fg)'(-2) is ugly notation that means find the derivative at x=-2
i.e.
(fg)'(-2) = f(-2) * g'(-2) + g(-2) * f'(-2)

Answer 9

5?

Answer 10

what is f(-2) ? and g'(-2)
then multiply together?

Answer 11

55

Answer 12

and g(-2) * f'(-2) ?

Answer 13

115

Answer 14

yes. It looks like you lost a minus sign the first time

Answer 15

Okay what about the next one Quotient rule?

Answer 16

unless there is a typo, I don't see any derivative in the 2nd problem
though the 3rd does use the quotient rule

Answer 17

There has to be a derivative for the second.. I am entering answers online.

Answer 18

wait... its -1

Answer 19

\[\frac{ 60-55 }{ 36 }\] for the 3rd one?

Answer 20

yes, 5/36

Answer 21

okay, what about this last one

Answer 22

?

Answer 23

it looks like the chain rule

Answer 24

mmm...

Answer 25

can you help me get started

Answer 26

I am stuck

Answer 27

I am not certain on this one. *maybe* we say f(-4)= -39
so we want d/dx g(x) at x= -39
i.e. g'(-39)

Answer 28

come on @phi let's not give up.