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limit of an = (2n^2)/(n^2+6) ?
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\[ \n^2+6\approx n^2 \] near infinity So how much is the limit?
\[ n^2+6 \approx n^2 \]
So \[ \frac {2 n^2}{n^2+6}\approx \frac {2 n^2}{n^2}=2 \] the limit is 2
Another way is to do the following \[ \frac{2 n^2}{n^2\left( 1 +\frac 6 {n^2} \right ) }=\frac{2 }{\left( 1 +\frac 6 {n^2} \right ) } \] It is easy now to see that the limit is 2
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