Question

(x/3)+(x/7)<2

Answer 1

it might help to multiply both sides by the LCD 21 to get...

\[\Large \frac{x}{3} + \frac{x}{7} < 2\]

\[\Large 21*\left(\frac{x}{3} + \frac{x}{7}\right) < 21*2\]

\[\Large 21*\left(\frac{x}{3}\right) + 21*\left(\frac{x}{7}\right) < 21*2\]

\[\Large 7x + 3x < 42\]

now those pesky fractions are gone

Answer 2

@cutegirl Look at the instructions for the problem. Are you to answer to the nearest integer, the nearest tenth, or some other way?

Answer 3

@cutegirl Solve the inequality posted by @jim_thompson5910

Answer 4

i was thinking d?

Answer 5

why D?

Answer 6

cause 7 times 3=21?

Answer 7

Look at the direction of the inequality of the problem.

Answer 8

10x<42

Answer 9

10x < 42 is correct so far

Answer 10

Solve for x: divide both sides of the inequality by 10.

Answer 11

x=<4.2

Answer 12

so its c?

Answer 13

I don't see 4.2 as an option but I do see its form as an improper fraction.
Look again at the options for a fraction that is the same as 4.2 and is a "less than" situation.

Answer 14

those are my choice so idk now

Answer 15

you divided both sides by 10 right? You should have

\[\Large x < \frac{42}{10}\]

reduce that to get your answer

Answer 16

thanks guys x<21/5

Answer 17

nailed it

Answer 18

Great @cutegirl