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Chemistry 10 Online
OpenStudy (anonymous):

MEDAL, FAN, TESTIMONIAL for the BEST EXPLANATION: Simple Question: Why are the units for the average rate and instantaneous rate the same? (unit: molarity/s) I know why, but I just can't put it in 'proper' way of explaining it lol. I hope you know what I mean.

OpenStudy (surry99):

Hint: how do the formulas for calculating average vs instantaneous rates differ?

OpenStudy (anonymous):

average, you're calculating the rate (slope) using two points (secant line) instantaneous, you're calculating the rate at a point (tangent line)

OpenStudy (surry99):

ok so the ratios are same the only real difference is the time interval. When we calculate an average rate delta t is finite. For an instantaneous rate, delta t becomes infinitesimally small

OpenStudy (anonymous):

uhuh.......okkkaaayyyyyyyyy........i know that...........hmmm.. im just having trouble with the wording, if i just explain it just like that, it's really idk nvm. thanks anyway :)

OpenStudy (surry99):

If you know calculus it is in the notation. For average changes we say delta concentration/delta time for instantaneous rates it becomes dc/dt where the d represents infinitely small quantities Good night!

OpenStudy (jfraser):

The only difference between average and instantaneous rates is the "width" of the time interval, as noted above. In a graph of concentration vs. time, the y-axis will always be molarity and the x-axis will always be time. The instantaneous rate will be a very narrow window of time but the units will be the same

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