Question

if 3x+3y-1,4x2+y-5,4x+2y are the sides of an equilateral triangle ,its area is closet to the integer
a)84
b)85
c)86
d)87

Answer 1

i want explanasion

Answer 2

its c i took this test question

Answer 3

how it came @DoveOliviaCameron

Answer 4

@mayankdevnani

Answer 5

@sreekar369 I think you have to provide some numerical data, please

Answer 6

they didnt given any other information,they asked to find area@Michele_Laino

Answer 7

@sreekar369 are you sure that the equations you provided are corrected?

Answer 8

yes

Answer 9

@sreekar369 your area is: \[84.77\approx 85\]

Answer 10

how u got it @Michele_Laino

Answer 11

I't simple, what you have are the measures of the sides of the equlateral triangle. So those measures have to be equal each other, so you have to solve the two equations below:
\[3x+3y-1=4x+2y\]
\[4x ^{2}+y-5=4x+2y\]
if you solve the above system for y, you will get two values for y, but note that only one value of y is acceptable.
I will give the acceptable solution:
\[y=3, x=2\]
other solution for y, namely:
\[y=1/4, x=-3/4\]

is not acceptable.
Now, with the right x and y values, you have to substitute them in your three equations, which are the measures of the sides of your triangle. the mesure of the side of your equilateral triangle is 14. FInally the area of your triangle is:
\[14*\frac{ \sqrt{3} }{ 2 }*14*\frac{ 1 }{ 2 }=84.77\]

Answer 12

ok thqs

Answer 13

thanks!

Answer 14

i kept another question once u see it @Michele_Laino

Answer 15

Ok!

Answer 16

@sreekar369 what is your new question, please?

Answer 17

i will tag u in tht