Question

How would I solve this?
Please include explanation.

Answer 1

6. The decay of an isotope is represented by the graph below.
https://app41.studyisland.com/pics/151984isotope.png


About how many grams of the isotope will remain after 27 days?

Answer 2

will fan and medal!

Answer 3

@marylou004
@prettyprincess1
@goatdude101

Answer 4

whats up ??

Answer 5

none

Answer 6

4.64g I think

use the formula of:
(in the attachment)

Answer 7

Thank you so much! May I ask another question?

Answer 8

that was my next guess

Answer 9

:)

Answer 10

What the the formula stand for and what number would I plug in?

Answer 11

*does

Answer 12

However while that is close it is not one of the answers here are the answers:

2.49
0.01
4.97
4.22

Answer 13

thats the options to choose from

Answer 14

I would say either 4.97 or 4.22. I am only 16 years old and, I have no experience in this topic.

Answer 15

Thank you either way!

Answer 16

But, I do enjoy physics

Answer 17

let \[y=k e ^{\alpha t}\]
where k & \[\alpha \] are constants.
when t=0 ,y=400
\[400=k e^0,k=400\]
\[\therefore ~y=400 e ^{\alpha t}\]
when t=1,y=340
\[340=400 e^\alpha ,e^\alpha=\frac{ 340 }{ 400 }=\frac{ 17 }{ 20 }\]
hence \[y=\left( \frac{ 17 }{ 20 } \right)^t,or~y=\left( 0.85 \right)^t\]

Answer 18

Thank you all so much for your help!

Answer 19

when t=27
y=?

Answer 20

correction
\[y=400\left( 0.85 \right)^t\]
\[y=400\left( 0.85 \right)^{27}=?\]

Answer 21

you got it.

Answer 22

i forgot to write 400 in the end of my calculation.
actually it is \[y=400 \left( \frac{ 17 }{ 20 } \right)^t=400\left( 0.85 \right)^{t}\]