There are 6 girls and 7 boys in a class. A team of 10 players is to be selected from the class. If the selection is random, what is the probability of selecting a team of 5 girls and 5 boys?

Question

anonymous · Answer

This may help you:

anonymous · Answer

$$P=\frac{ c_{5}^{6}*_c{5}^{7} }{ c _{10}^{13} }=?$$

anonymous · Answer

$$P=\frac{ c_{5}^{6}*c _{5}^{7} }{ c _{10}^{13} }$$

anonymous · Answer

remember$$c _{r}^{n}=c _{n-r}^{n}$$

anonymous · Answer

$$c _{5}^{6}=c _{6-5}^{6}=c _{1}^{6}=\frac{ 6 }{ 1 }=6$$
$$c _{5}^{7}=c _{7-5}^{7}=c _{2}^{7}=\frac{ 7*6 }{ 2*1 }=21$$
$$c _{10}^{13}=c _{13-10}^{13}=c _{3}^{13}=\frac{ 13*12*11 }{ 3*2*1 }=286$$
find p

anonymous · Answer

I have problems comprehending equations like that. Is there a simpler way to do it?