Question

Identify the horizontal asymptote of f(x) = quantity 6 x minus 7 over quantity 11 x plus 8.

Answer 1

a. 0
b. y=6/11
c. -7/8
d. no horizontal asymptote

Answer 2

@dan815

Answer 3

I don't understand the formula for f(x), please can you write it better?

Answer 4

6x - 7/11x + 8

Answer 5

if \[f(x)=6x-\frac{ 7 }{ 11x }+8\], we have:
\[\lim _{x \rightarrow \pm \infty} f(x)=\pm \infty \]
so we have not horizontal asymptotes

Answer 6

okay thank you. very helpful

Answer 7

thank you!

Answer 8

there is a horizontal asymptote... a simple way to look at the problem

the degree of the numerator and denominator are the same,
the horizontal asymptote is the ratio of the coefficients

\[y = \frac{6x - 7}{11x+ 8}\]

both are degree 1

so the horizontal aysmptote is

\[y = \frac{6}{11}\]

to check graph it using https://www.desmos.com/calculator

Answer 9

I think the confusion has occurred because of the way the expressions have been written

Answer 10

oh okay thanks