SOME ONE PLEASE HELP The steps to derive the quadratic formula are shown below: Step 1: ax2 + bx + c = 0 Step 2: x2 + b over ax + c over a = 0 Step 3: x2 + b over a x = - c over a Step 4: x2 +b over a x + square of quantity of b over 2 times a = -c over a + square of quantity of b over 2 times a Step 5: x plus b over 2 times a, all squared = -c over a + square of quantity of b over 2 times a Step 6: x + b over 2 times a = square root of all of negative c over a plus the square of the quantity b over 2 times a Step 7: x = - b over 2 times a ± square root of all of negative c over a plus

Question

SOME ONE PLEASE HELP The steps to derive the quadratic formula are shown below:  Step 1: ax2 + bx + c = 0 Step 2: x2 + b over ax + c over a = 0 Step 3: x2 + b over a x = - c over a Step 4: x2 +b over a x + square of quantity of b over 2 times a = -c over a +  square of quantity of b over 2 times a Step 5: x plus b over 2 times a, all squared = -c over a +  square of quantity of b over 2 times a Step 6: x + b over 2 times a =   square root of all of negative c over a plus the square of the quantity b over 2 times a  Step 7: x = - b over 2 times a ±  square root of all of negative c over a plus

anonymous · Answer

Which step is wrong

anonymous · Answer

I don't see anything wrong. You do need to finish.$$(x+\frac{ b }{ 2a })^{2}=-\frac{ c }{ a}
+(\frac{ b }{ 2a })^{2}$$$$x+\frac{ b }{ 2a }=\pm \sqrt{-\frac{ c }{ a}+(\frac{ b }{ 2a })^{2}}$$$$x=-\frac{ b }{ 2a }\pm \sqrt{-\frac{ c }{ a }+(\frac{ b }{ 2a })^{2}}$$Finishing
$$x=-\frac{ b }{ 2a }\pm \sqrt{\frac{ b ^{2} }{ 4a ^{2} }-\frac{ 4ac }{ 4a ^{2} }}$$$$x=-\frac{ b }{ 2a }\frac{ \pm \sqrt{b ^{2}-4ac} }{ \pm \sqrt{4a ^{2}} }$$$$x=-\frac{ b }{ 2a }\pm \frac{ \sqrt{b ^{2}-4ac} }{ 2a }$$