Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
write in trig form first
OpenStudy (anonymous):
you know how to do that?
OpenStudy (anonymous):
Ummm. 10(cos60 - isin(60)
OpenStudy (anonymous):
not sure about the 10 l
OpenStudy (anonymous):
\[\sqrt{5^2+(5\sqrt3)^2}\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh you win 10
but there is a mistake there
OpenStudy (anonymous):
it should be
\[10\left(\cos(\theta)+i\sin(\theta)\right)\] not minus
OpenStudy (anonymous):
Gotcha
OpenStudy (anonymous):
angle is not 60
OpenStudy (anonymous):
dang draw tool is not working
if you can draw it you will you are in quadrant 4, not 1
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Would it be... 300?
OpenStudy (anonymous):
yeah i guess
if you are working in degrees
OpenStudy (anonymous):
now you want the fifth roots
take \(\sqrt[5]{10}\) as the modulus, and divide the angle by 5
so the first answer will be
\[\sqrt[5]{10}\left(\cos(60)+i\sin(60)\right)\]
OpenStudy (anonymous):
Okay...
OpenStudy (anonymous):
What about the other four?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
one way to do it is to divide the circle up in to five equal parts, with \(60\) degrees as one of them
the other way is to keep adding 360 to the angle and divide by 5 again
\[660\div 5=132\] so the next one is \[\sqrt[5]{10}\left(\cos(132)+i\sin(132)\right)\]