Question

A force of 18 Newtons stretches a spring 2 centimeters. A 225 kilogram mass is placed on the end of the spring, stretched from equilibrium and released resulting in undamped free force. What is the period of oscillation of the mass?

Answer 1

So you have to determine k, then using something about sum all the forces =0 at equilib. you determine the period at oscilation

Answer 2

how do you determine k?

Answer 3

4050

Answer 4

or 2025

Answer 5

How did you get 2025? Can you show your work?

Answer 6

shouldn't k be 18N/.02m=900 n/m

Answer 7

do you know the formula for k?

Answer 8

k=18N/.02m=900 N/m
m=225 kg
T=2pi (m/k)^.5=pi

Answer 9

I agree

Answer 10

Is that correct?

Answer 11

yup so long as your eq for period is correct