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Chemistry 10 Online
OpenStudy (anonymous):

What is the reducing agent in the following reaction? 2Na + 2H2O → 2NaOH + H2 H2 NaOH H2O Na

OpenStudy (cuanchi):

first reaction Na second reaction H2

OpenStudy (anonymous):

3) Na(s) + 2H2O(l) --> 2NaOH(aq) + H2(g) Na(s) --> Na+(aq) + e- ==> Na(s) is oxidized so it is a reducing agent 2H2O(l) + 2e- --> 2OH-(aq) + H2(g) ==> H2O is reduced so it is an oxidizing agent Answer 1

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

Your welcome! Hope it help you....<3

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