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Mathematics 21 Online
OpenStudy (anonymous):

How many solutions does the equation have? http://static.k12.com/bank_packages/files/media/mathml_432c5ef2080fdafcf77c86eb4174ca1530c9782b_1.gif A. one solution B. infinite solutions C. no solution

OpenStudy (anonymous):

@Bibbys_Husky

OpenStudy (anonymous):

@uri

OpenStudy (anonymous):

@samson245

OpenStudy (anonymous):

@sammixboo

OpenStudy (anonymous):

@Abhisar

OpenStudy (anonymous):

I give medals

OpenStudy (anonymous):

can you eplane though xD

OpenStudy (ivycoveredwalls):

\[a+5=\frac{1}{5}(5a+25)\] Hint: what do you get when you apply the Distributive Property to the right side of your equation? (Multiply both 5a and 25 by 1/5)?

OpenStudy (anonymous):

multiply 1/5

OpenStudy (ivycoveredwalls):

yes, "multiply out" the right-hand side of the equation.

OpenStudy (anonymous):

so how would i write it down

OpenStudy (ivycoveredwalls):

\[a+5=\frac{1}{5}(5a)+\frac{1}{5}(25)\] Now multiply both 5a and 25 by 1/5.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

and then i?

OpenStudy (ivycoveredwalls):

You should have an equation that says a + 5 = a + 5. That looks kinda special, doesn't it? Normally, you'd try to get the variable by itself. Try subtracting 5 from both sides. You get a = a. How many numbers do you think are equal to THEMSELVES?!

OpenStudy (anonymous):

so B right?

OpenStudy (ivycoveredwalls):

Yes! This kind of equation is called an IDENTITY because the two sides are identical, although in this case, the right side is sort of "in disguise." It's not as obvious as, say, the equation x + 1 = x + 1.

OpenStudy (anonymous):

so infinite mean like there equal

OpenStudy (ivycoveredwalls):

Yeah! If you try to solve the equation x + 1 = x + 1, you subtract 1 from both sides and get x = x. This is saying that any solution is a number equal to itself. But ALL numbers are equal to themselves. Any real number is a solution to the equation.

OpenStudy (anonymous):

okay thanx alot xD Medal For the smart bueatiful girl xD your awsume

OpenStudy (ivycoveredwalls):

Happy to help!

OpenStudy (anonymous):

How many solutions does the equation have? 3(4x-3)-7x=5x-9 A. one solution B. infinite solutions C. no solution

OpenStudy (anonymous):

this what i did 3(4x-3) - 7x = 4x 12x-3-7x=4x

OpenStudy (anonymous):

@ivycoveredwalls did i do it right so far?

OpenStudy (anonymous):

@felavin

OpenStudy (anonymous):

@nechirwan

OpenStudy (anonymous):

it's C.

OpenStudy (ivycoveredwalls):

Almost correct. Look carefully at the left side. When you distribute the 3, you must multiply it by BOTH terms inside parentheses. 3(4x - 3) - 7x = 5x - 9 12x - 9 - 7x = 5x - 9 Now combine terms on the left side (put the 12x and 7x together using subtraction). You'll get 5x - 9 = 5x - 9. Does this look familiar?

OpenStudy (anonymous):

oh ya i messed up on the pat where it was 12x-9 i put 12x-3 lol

OpenStudy (ivycoveredwalls):

That's really easy to do!

OpenStudy (anonymous):

you don't solve for 5x-9?

OpenStudy (anonymous):

ikr i meesed up sorry

OpenStudy (anonymous):

@Ivanloza96

OpenStudy (ivycoveredwalls):

Nope. As soon as you see that the two sides of the equation are the same, you can say that the number of solutions is infinite. But if something like this happens: 3(2x + 3) = 6x + 7 6x + 9 = 6x + 7 If you subtract 6x from both sides, you get 9 = 7, which is NOT TRUE! That's telling you that there are NO SOLUTIONS!

OpenStudy (anonymous):

oh okay

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