Question

HELP ME???
http://assets.openstudy.com/updates/attachments/54464e8be4b01aa966fc56b5-saylilbaby-1413893797980-aunit6portfolio1.pdf

Answer 1

ok so first plot the points

Answer 2

use that formula to find the distance between two points, let start with the first one, the distance between Point A and point B

Answer 3

So plug in

Answer 4

point A = (-1, 4) point B = (1,1)

Answer 5

\[\sqrt{(1--1)^{2}+(1-4)^{2}}\]

Answer 6

=13

Answer 7

i got 4+-6

Answer 8

can I see what you did?

Answer 9

i did what you did but for y2-y1 i used a calculator to do 1-4 times 2

Answer 10

no, 1-4= -3 then you square that, you don't multiply it by 2

Answer 11

\[-3^{2}\]
simply means you multiply -3 times -3

Answer 12

when you multiply a negative times a negative you get a positive so -3 x -3 equals 9

Answer 13

Ill try the next one umm lets see..

Answer 14

-3--1+-1--4?

Answer 15

Waist a minute, let's go back to the first one, AB, we forgot to square root it lol so the distance of point A and point B is \[\sqrt{13}\]

Answer 16

13x13?

Answer 17

and which one is that one you are doing right now?

Answer 18

no, square root is the oposite of sqauring

Answer 19

square root: \[\sqrt{x}\]

Sqauring or power of two: \[x^{2}\]

Answer 20

3.60?

Answer 21

yes, that is for AB right?

Answer 22

yes, is that the answer?? Like for real??

Answer 23

yes, you can leave it as \[\sqrt{13}\] though if you want

Answer 24

Now the nest one point B and C

Answer 25

4+3=7?

Answer 26

\[\sqrt{(-1-1)^{2}+(-4-1)^{2}}\]

Answer 27

Oh yeahhh! I need to try again real quick

Answer 28

\[\sqrt{(-2)^{2}+(-5)^2}\]

Answer 29

4+25

Answer 30

yes :) and then find the square root of that

Answer 31

\[\sqrt{29}\]

Answer 32

yes now do CD

Answer 33

4+3?

Answer 34

\[\sqrt{(-3-(-1))^2+(-1-(-4))^2}\]

Answer 35

\[\sqrt{(-2)^2+(3)^2}\]

Answer 36

How?

Answer 37

-4+9??

Answer 38

oh so when there are two negative sings (-) to each other then those two negatives become positive so it 'd be\[\sqrt{(-3+1)^2+(-1+4)^2}\]

Answer 39

so 4+9

Answer 40

yes the square root of that is the distance between point c and point d

Answer 41

\[\sqrt{13}\] ??

Answer 42

yes or 3.60

Answer 43

so you see how the distance between Point A and Point B is the same as the distance between Point C and Point D?

Answer 44

They are congruent?

Answer 45

Now look at your graph, do you see the sides that are congruent?

Answer 46

yes, opposite sides are congruents, so that means that the shape is a parallelogram

Answer 47

so DA=4+25?

Answer 48

\[\sqrt{29}\]

Answer 49

Now let's find the slope, which is rise over run

Answer 50

or rate of change

Answer 51

\[S=\frac{ y_{2}-y_{1} }{ x_{2}-x_{2} }\]

Answer 52

x2?

Answer 53

oops I mean x1 sorry

Answer 54

-3 and 2??

Answer 55

Yeah but in a fraction so -3/2

Answer 56

and thats my anwser?

Answer 57

yes :)

Answer 58

No BC

Answer 59

-5/2?

Answer 60

no it is positive 5/2

Answer 61

\[\frac{ -4-1 }{ -1-1 }= \frac{ -5 }{ -2 } = \frac{ 5 }{ 2 }\]

Answer 62

When you divide or multiply numbers with the SAME signs, the answer is positive, different signs, the answer is negative

Answer 63

but we subtracted?

Answer 64

-4 minus 1 is -5
-1 minus 1 is -2

Answer 65

yes but we only subtracted the numbers in the numerators with the numbers in the numerator and subtracted the numbers in the denominator with the numbers in the denominator

Answer 66

then we are left with a fraction, which is the same as division

Answer 67

OH YEAH!! I feel stupid ^.^ um so CD= 3/2?

Answer 68

No, close but it is actually 3/-2 or just -3/2

Answer 69

-.- that was my first guess. Then DA=5/2

Answer 70

\[\frac{(-1-(-4)) }{( -3-(-1))}\]

Answer 71

yes :) because side DA and side BC are parallel to each other ^_^

Answer 72

and so are sides AB and CD

Answer 73

they have the same slope because they are parallel

Answer 74

Are there any perpendicular?

Answer 75

yes
A line is perpendicular to another if it meets or crosses it at right angles (90°).

Answer 76

I dont see any on the chart

Answer 77

oops my bad actually no a parallelogram DOES not have perpendicular lines see why?

Answer 78

Yep ^.^ What about my diagonal slope answers? I have no clue at all

Answer 79

ok, just use the slope formula ;)

Answer 80

they are talking about the diagonal line between point A and Point C

Answer 81

can you visualize it? like look at the graph (not necessary though)

Answer 82

I can see it..but what about it?

Answer 83

just wanted you to know what they were talking about, ok so now just use the slope formula the same one we used to find the previous slopes.

Answer 84

-8/0?

Answer 85

yes, anything divided by 0 is simply 0 though

Answer 86

And can you see why the slope of the diagonal line between A and C is 0?

Answer 87

it's because it's just a straight line...there is no rate of change

Answer 88

Oh I heard that somewhere. Theres like a word for it though! and um.. BD=-2/-4

Answer 89

yeah it stays constant. and yeah that is correct :) it will become positive though because a negative divided by a negative is positive

Answer 90

Now look at your graph, try to draw the two diagonal lines

Answer 91

if you haven't already done so.

Answer 92

are the diagonals perpendicular?