Question

what is the derivative of xe^-2x?

Answer 1

The derivative of f(x)*g(x) is f(x)'*g(x)+f(x)*g(x)'
so the derivative of \(xe^{-2x}\) is
\[x'(e^{-2x})+x(e^{-2x})'\]
\[1*e^{-2x}+x(-2*e^{-2x})\]
\[e^{-2x}-2xe^{-2x}\]

Answer 2

Umm just to preface what i wrote above
the derivative of x=1
and thederivative of \(e^{-2x} \) is \(-2*e^{-2x}\)

Answer 3

the derivative is -2e^-2x?

Answer 4

dont you use the chain rule?

Answer 5

we used the product rule

Answer 6

Look at my first post. the derivative is \[e^{-2x}-2xe^{-2x}\]