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OpenStudy (anonymous):
Solve Bc 0.1=(Bc)/(100+Bc)
Please tell me process
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OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@zepdrix please help!
zepdrix (zepdrix):
Solve for Bc?
zepdrix (zepdrix):
\[\Large\rm 0.1=\frac{B_c}{100+B_c}\]
zepdrix (zepdrix):
Let's multiply both sides by 10, so we don't have to deal with a decimal value.\[\Large\rm 1=\frac{10B_c}{100+B_c}\]
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zepdrix (zepdrix):
Multiply both sides by (100+Bc),\[\Large\rm 1(100+B_c)=10B_c\]\[\Large\rm 100+B_c=10B_c\]
Understand how to solve it from there?
Any steps confusing?
OpenStudy (anonymous):
I understand so far. next step is not sure.
zepdrix (zepdrix):
Combine like terms.
Get the B's on the same side.
OpenStudy (anonymous):
Bc=10Bc-100?
zepdrix (zepdrix):
You moved the 100 to the other side....
You want your B's on the same side.
You don't want to move the 100.
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zepdrix (zepdrix):
Subtract B from each side.
OpenStudy (anonymous):
ok.
100-10Bc=Bc?
OpenStudy (anonymous):
@zepdrix
zepdrix (zepdrix):
???
zepdrix (zepdrix):
\[\Large\rm 100+B_c=10B_c\]Subtract B from each side,\[\Large\rm 100=10B_c-B_c\]
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OpenStudy (anonymous):
100=9Bc!!
OpenStudy (anonymous):
ah. then Bc=9/100?
zepdrix (zepdrix):
yes!
OpenStudy (anonymous):
Thankk you soo much!!
zepdrix (zepdrix):
np c:
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