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negate the statement below
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hu?
\[(\forall y \in \mathbb{R}) [y>0 \implies (\exists x \in \mathbb{R} s.t. (y=e^x)]\]
Recall that:\[\Large\rm P\implies Q \qquad\equiv\qquad \neg P \wedge Q\]
So let's see....
\[\Large\rm \forall y \in \mathbb{R}, \qquad y>0 \implies (\exists x \in \mathbb{R}:y=e^x)\]So we want to negate this.. ummm So we'll write it as:\[\Large\rm \forall y \in \mathbb{R}, \qquad y\le0 ~or~ (\exists x \in \mathbb{R}:y=e^x)\]It should be a little easier to negate from here, yes?
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I changed the interval for y, (changed it to NOT p)
\[\Large\rm \exists y\in \mathbb R:\qquad y\gt0~and~(\forall x\in\mathbb R,\quad y\ne e^x)\]Something like that I think. Yah?
i think so, thank you!
np c:
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