Stoichiometry: Limiting reagent
Is this enough information for you to help me out?
I'm not sure. But for me, I don't think there's enough info. They are just balanced equation. Do they tell you like how many grams of each element is used in the reaction?
Sure, 'll give you all of those information. Wait a minute.
All of them are in the same order like the one above.
oh. this isnt that bad. they even solved it for you. look at the last column (left over) the limiting reagent is the one with fewer number of leftovers
and i think the last one is special. since both are used up, there is no limiting reagents
Lol, I solved it but kinda confused on the question I posted. So the last one has no limiting reagents? N/A.
oh. i thouhgt those were given. and yea, last one should be N/A
limiting reagent is that one that is used up in the reaction before the other reactant
Thanks, do you know the other two?
yea. look at the one with ) leftover. that would be your limiting reagent
^0 leftover
Hmm, is it okay if you could show me how to correctly get that? Sorry, just need to understand.
ok. lets lok at the second one for the leftover column, you have 9N2 and 0H2 this shows you have 9 moles of N2 left and 0 moles of H2 left. because there are 0 moles of H2 left after the reaction, that means that it is the limiting reagent
the H2 limited your reaction. it was all used up in the reaction. That also means you have an excess of N2, which you dont have to worry about in your problem.
Oh alright, so overall, the second column would be 0 for the answer, that it?
what do you mean second column would be 0?
We're solving the second column right?
oh. i thought we were answering your question.
If H2 is the limited reaction, how come 9N2 wouldn't be the the amount of the reaction?
I feel so dumb for asking all of these questions.
|dw:1416810396705:dw| so you have your balance equation and your reactants
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