Question

help w this question ??

Answer 1

yes he is correct?

Answer 2

is it clear that the diagonal OM is \(6\sqrt2\) ?

Answer 3

no, it is not? @satellite73

Answer 4

ok then lets make sure it is clear

Answer 5

by pythagoras,
\[6^2+6^2=d^2\\
2\times 6^2=d^2\\
\sqrt{2\times 6^2}=d\\
6\sqrt2=d\]

Answer 6

more generally the diagonal of a square with side \(a\) is \(a\sqrt2\)

Answer 7

now use pythagoras again to find the diagonal here

Answer 8

13.42?

Answer 9

\[12^2+6^2=d^2\\
\sqrt{12^2+6^2}=d\]

Answer 10

forget decimals

Answer 11

1342?

Answer 12

or just 13

Answer 13

just use radicals
\[\sqrt{144+36}=\sqrt{180}=6\sqrt5\]

Answer 14

in any case
\[6\sqrt5\] is not 2 times \(6\sqrt2\) so the answer is NO