how do I find the zeros (roots) of x^2+9
well they will be complex you are solving an equation... so you need to let \[x^2 + 9 = 0\] you need to find the values of x that make the equation zero... and there will be 2 zeros as its a quadratic equation. subtract 9 from both sides of the equation and then take the square root of both sides. one solution will be positive and the other negative hope it helps
so like x+3 and x-3?
not quite... do it step by step... subtract 9 from both sides of the equation... what do you get?
x=-9
well x^2=-9
nearly \[x^2 = -9\] now take the square root of both sides..
it would be x and the sqr root 3 i?
so is it root 3 i?
positive and negative
well nearly \[x= \pm \sqrt{-9} ~~~or~~~ x = \pm \sqrt{9i^2}\] so hopefully this will help you get the answer...
sweet thanks
you don't need the root since 9 is a square number
alrighty thanks dude
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